Name :
Grade :
School :
Guide :
Time : 60 minutes
MATH
OLYMPIC GLORYPOWEROCK
1. What
day of the week does May 28 2006 fall on
|
2. What
will be the day of the week 15th August, 2010?
3. Today
is Monday. After 61 days, it will be
|
4. On what
dates of April, 2001 did Wednesday fall?
5. How
many days are there in x weeks x days
1. What day of the week does May
28 2006 fall on
|
|
A. Saturday
|
B. Monday
|
C. Sunday
|
D. Thursday
|
Answer: Option C
Explanation:
28th May 2006 = (2005 years + period
from 1-Jan-2006 to 28-May-2006)
We know that number of odd days in 400 years = 0
Hence the number of odd days in 2000 years = 0 (Since 2000 is a perfect multiple of 400)
Number of odd days in the period 2001-2005
= 4 normal years + 1 leap year
= 4 x 1 + 1 x 2 = 6
Days from 1-Jan-2006 to 28-May-2006 = 31 (Jan) + 28 (Feb) + 31 (Mar) + 30 (Apr) + 28(may)
= 148
148 days = 21 weeks + 1 day = 1 odd day
Total number of odd days = (0 + 6 + 1) = 7 odd days = 0 odd day
0 odd day = Sunday
Hence May 28 2006 is Sunday.
We know that number of odd days in 400 years = 0
Hence the number of odd days in 2000 years = 0 (Since 2000 is a perfect multiple of 400)
Number of odd days in the period 2001-2005
= 4 normal years + 1 leap year
= 4 x 1 + 1 x 2 = 6
Days from 1-Jan-2006 to 28-May-2006 = 31 (Jan) + 28 (Feb) + 31 (Mar) + 30 (Apr) + 28(may)
= 148
148 days = 21 weeks + 1 day = 1 odd day
Total number of odd days = (0 + 6 + 1) = 7 odd days = 0 odd day
0 odd day = Sunday
Hence May 28 2006 is Sunday.
2. What will be the day of the
week 15th August, 2010?
|
|
A. Saturday
|
B. Monday
|
C. Sunday
|
D. Thursday
|
Answer: Option C
Explanation:
15th Aug 2010 = (2009 years + period
from 1-Jan-2010 to 15-Aug-2010)
We know that number of odd days in 400 years = 0
Hence the number of odd days in 2000 years = 0 (Since 2000 is a perfect multiple of 400)
Number of odd days in the period 2001-2009
= 7 normal years + 2 leap year
= 7 x 1 + 2 x 2 = 11 = (11 - 7x1) odd day = 4 odd day
Days from 1-Jan-2010 to 15-Aug-2010
= 31 (Jan) + 28 (Feb) + 31 (Mar) + 30 (Apr) + 31(may) + 30(Jun) + 31(Jul) + 15(Aug)
= 227
227 days = 32 weeks + 3 day = 3 odd day
Total number of odd days = (0 + 4 + 3) = 7 odd days = 0 odd day
0 odd day = Sunday
Hence 15th August, 2010 is Sunday.
We know that number of odd days in 400 years = 0
Hence the number of odd days in 2000 years = 0 (Since 2000 is a perfect multiple of 400)
Number of odd days in the period 2001-2009
= 7 normal years + 2 leap year
= 7 x 1 + 2 x 2 = 11 = (11 - 7x1) odd day = 4 odd day
Days from 1-Jan-2010 to 15-Aug-2010
= 31 (Jan) + 28 (Feb) + 31 (Mar) + 30 (Apr) + 31(may) + 30(Jun) + 31(Jul) + 15(Aug)
= 227
227 days = 32 weeks + 3 day = 3 odd day
Total number of odd days = (0 + 4 + 3) = 7 odd days = 0 odd day
0 odd day = Sunday
Hence 15th August, 2010 is Sunday.
3. Today is Monday. After 61 days,
it will be
|
|
A. Sunday
|
B. Saturday
|
C. Monday
|
D. Thursday
|
Answer: Option B
Explanation:
61 days = 8 weeks 5 days = 5 odd
days
Hence if today is Monday, After 61 days, it will be = (Monday + 5 odd days)
= Saturday
Hence if today is Monday, After 61 days, it will be = (Monday + 5 odd days)
= Saturday
4. On what dates of April, 2001
did Wednesday fall?
|
|
A. 2nd, 9th,
16th, 23rd
|
B. 1st, 8th,
15th, 22nd, 29th
|
C. 4th, 11th,
18th, 25th
|
D. 3rd, 10th,
17th, 24th
|
Answer: Option C
Explanation:
We need to find out the day of
01-Apr-2001
01-Apr-2001 = (2000 years + period from 1-Jan-2001 to 01-Apr-2001)
We know that number of odd days in 400 years = 0
Hence the number of odd days in 2000 years = 0 (Since 2000 is a perfect multiple of 400)
Days from 1-Jan-2001 to 01-Apr-2001 = 31 (Jan) + 28 (Feb) + 31 (Mar) + 1(Apr) = 91
91 days = 13 weeks = 0 odd day
Total number of odd days = (0 + 0) = 0 odd days
0 odd day = Sunday. Hence 01-Apr-2001 is Sunday.
Hence first Wednesday of Apr 2011 comes in 04th and successive Wednesdays come in 11th, 18th and 25th
01-Apr-2001 = (2000 years + period from 1-Jan-2001 to 01-Apr-2001)
We know that number of odd days in 400 years = 0
Hence the number of odd days in 2000 years = 0 (Since 2000 is a perfect multiple of 400)
Days from 1-Jan-2001 to 01-Apr-2001 = 31 (Jan) + 28 (Feb) + 31 (Mar) + 1(Apr) = 91
91 days = 13 weeks = 0 odd day
Total number of odd days = (0 + 0) = 0 odd days
0 odd day = Sunday. Hence 01-Apr-2001 is Sunday.
Hence first Wednesday of Apr 2011 comes in 04th and successive Wednesdays come in 11th, 18th and 25th
5. How many days are there in x
weeks x days
|
|
A. 7
|
B. 14x
|
C. 7x2
|
D. 8x
|
Answer: Option D
Explanation:
xx weeks xx days =(7×x)+x=7x+x=8x=(7×x)+x=7x+x=8x days
